Answer:
There are 0.408 moles of CO
Explanation:
Ideal gases Law to solve this excersise
P . V = n . R . T
Pressure = 2.80 atm
Volume = 5 L
T° = 155°C
T° K = T°C + 273 = 428K
R = 0.082 l.atm/mol.K
2.80 atm . 5l = n . 0.082 . 428K
(2.80 atm . 5l) / (0.082 . 428K) = n
0.408 mol = n
