marrissajade7762 marrissajade7762
  • 20-04-2018
  • Mathematics
contestada

If y varies directly as x2 and y=290 when x=12, find y if x=18

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Аноним Аноним
  • 20-04-2018
y varies directly with x²

[tex]\boxed {\boxed {y = kx^2}}[/tex]

When x = 12, y = 290

[tex]290 = k(12)^2[/tex]

[tex]144k = 290[/tex]

[tex]k = \dfrac{290}{144} [/tex]

[tex]k = \dfrac{145}{72} [/tex]

[tex]\boxed {\boxed {y = \dfrac{145x^2}{72} }}[/tex]

When y - 18

[tex]y = \dfrac{145(18)^2}{72}[/tex]

[tex]y = 652.5[/tex]

[tex]\boxed { \boxed { \text {Answer: y = 652.5}}}[/tex]

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