An echocardiogram uses 4.4 mhz ultrasound to measure blood flow in the aorta. the blood is moving away from the probe at 1.5 m/s . the speed of sound medium speed (m/s) air (0∘c) 331 air (20∘c) 343 helium (0∘c) 970 ethyl alcohol 1170 water 1480 human tissue (ultrasound) 1540 lead 1200 aluminium 5100 granite 6000 diamond 12,000 you may want to review ( pages 489 - 492) . part a what is the frequency shift of the reflected ultrasound

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The solution for this problem would be using this formula:Δf / f = 2v / c gives a very good approximate when c >> v, as in this problem. 
Δf / 4.4e6Hz = 2 * -1.5m/s / 1540m/s Δf = 2 * -1.5m/s / 1540m/s / 4400000Δf = - 8571.43 Hz  would be the answer