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Identify an equation in point-slope form for the line perpendicular to y = 3x + 5 that passes through (4, –1). A.y-4=-1/3(x+1) B.y+1=3(x-4) C.y-1=-3(x+4) D.Y+1=-1/3(X-4)

Respuesta :

m=-1/3
y-y1=m(x-x1)
y+1=-1/3(x-4)
musiclover10045

the slope of the given formula y=3x+5 is 3

 a perpendicular line has a slope that is a negative reciprocal

 so that would be -1/3, so the answer needs to have -1/3 in it, that leaves you A and D

 the formula for point slope is y-y1=m(x-x1)

y1 = -1 and x1 = 4

 so you get: y+1=-1/3(x-4)

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