maty1
maty1
17-05-2015
Mathematics
contestada
how would you solve 3sin0=sin0-1
Respuesta :
AL2006
AL2006
17-05-2015
I would subtract 1sin(Θ) from each side of the equation.
The equation would then say that 2sin(Θ) = -1 .
I would only have to find angles whose sin is -1/2 ,
and those would be my solutions.
Answer Link
Panoyin
Panoyin
17-05-2015
3sinΘ = sinΘ - 1
3sinΘ - sinΘ = sinΘ - sinΘ - 1
2sinΘ
=
-1
2sin 2sin
Θ = -2.864934497
Answer Link
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