demitae391 demitae391
  • 17-06-2017
  • Mathematics
contestada

How many solutions does the equation sin(4x)=1/2 have on the interval (0 2pi)?

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Аноним Аноним
  • 18-06-2017
the angle < pi/2  and whose sine is 1/2 is pi/6

so let 4x = pi/6 and we have x = pi/24   which is one solution.

angle in second quadrant = 5pi / 6  so x = 5pi/24 is another solution.

Each of these  will give new angles as we revolve around the circle in steps of pi/2  so for x = pi/24 next one will be 13pi/24  and for x = 5pi/24 next one will be 17pi/24    This will be true for all angles less than  48pi/24  (ie 2pi)

so there will be 8 solutions 
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haroldlangley1374 haroldlangley1374
  • 24-01-2021

Answer: 8 solutions

Step-by-step explanation: ap3x :)

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