Respuesta :

LammettHash
[tex]z^3=-1+i\sqrt3=2e^{i2\pi/3}[/tex]

[tex]\implies z=\left(2e^{i2\pi/3}\right)^{1/3}=\begin{cases}2^{1/3}e^{i2\pi/9}\\2^{1/3}e^{i8pi/9}\\2^{1/3}e^{i14\pi/9}\end{cases}[/tex]