samrockz
samrockz
17-04-2015
Mathematics
contestada
Solve this equation by factoring
6n^2-18n-18=6
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konrad509
konrad509
17-04-2015
[tex] 6n^2-18n-18=6 \\ 6n^2-18n-24=0\\ n^2-3n-4=0\\ n^2+n-4n-4=0\\ n(n+1)-4(n+1)=0\\ (n-4)(n+1)=0\\ n=4 \vee n=-1[/tex]
Answer Link
dln
dln
17-04-2015
[tex]6n^{2}-18n-18=6 \\ 6n^{2}-18n-24=0 \\ 6(n^{2}-3n-4)=0 \\ 6(n-4)(n+1)=0 \\ \boxed{n=4\ and\ -1}[/tex]
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