princess010611 princess010611
  • 18-08-2022
  • Mathematics
contestada

u (x) = negative 2 x squared and v (x) = StartFraction 1 Over x EndFraction, what is the range of (u circle v) (x)

Respuesta :

profarouk profarouk
  • 18-08-2022

Answer:

(−∞, 0) ∪ (0, ∞)

Step-by-step explanation:

Given :

u(x) = -2x²

[tex]V(x)=\sqrt{\frac{1}{x} }[/tex]

Determining UoV(x) :

[tex]UoV(x)=U(V(x))=-2\left( \sqrt{\frac{1}{x} } \right)^{2}[/tex]

Then

[tex]UoV(x)=U(V(x))=-2 \times \frac{1}{x}[/tex]

Then

[tex]UoV(x)=U(V(x))=- \frac{2}{x}[/tex]

Since the range of  -2/x  is all real numbers except zero

Then

The range of UoV is :

(−∞, 0) ∪ (0, ∞)

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