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Two concentric circles are of radii 10 cm and 8 cm, then the length of the chord of the larger circle which touches the smaller circle is​

Respuesta :

Answer:

  • 12 cm

Step-by-step explanation:

Let O be the centre of the circle of radii 10 cm and 8 cm.

In given figure,

AP = PB and OP⊥AB

Applying Pythagoras theorem in ∆OPA, we get

↠ OA² = OP² + AP²

↠ (10)² = (8)² + AP²

↠ 100 = 64 + AP²

↠ 100 - 64 = AP²

↠ 36 = AP²

↠ √36 = AP

↠ 6 = AP

Now,

↠ AB = 2AP

↠ AB = 2(6)

↠ AB = 12 cm

Hence,

  • The length of the chord of the larger circle 12 cm
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