Respuesta :

Berkay1229
k greater than 1

(k-1)x>z
x>z/(k-1)

k less than 1

-z-y/(1-k)>x

k equal to 1

0>y+z
apologiabiology
kx-y≥x+z

minus x both sides
kx-x-y≥z
add y to both sides
kx-x≥y+z
undistribute x
x(k-1)≥y+z
divide both sides by (k-1)
[tex]x= \frac{y+z}{k-1} [/tex]

if k is greater than 1, then the denomenator is positive, then x is positive (assuming z+y is positive)

if k is les than 1, the the denomenator is negatve, then x is negative

if k is equal to 1, then x is undefined