jerricaK jerricaK
  • 21-02-2022
  • Mathematics
contestada

someone pls help me..

someone pls help me class=

Respuesta :

fieryanswererft
fieryanswererft fieryanswererft
  • 21-02-2022

Answer:

[tex]32x^2 \sqrt[3]{2x} - 8x^3[/tex]

Step-by-step explanation:

[tex]\hookrightarrow 4x\sqrt[3]{4x^2}\left(2\sqrt[3]{32x^2}-x^3\sqrt{2x}\right)[/tex]

[tex]\hookrightarrow 8x\sqrt[3]{32x^2 } \sqrt[3]{4x^2} -4x^2 \sqrt[3]{4x^2} \sqrt[3]{2x}[/tex]

[tex]\hookrightarrow 2^5\sqrt[3]{2}x^{\frac{7}{3}}-2^2\cdot \:2^{\frac{2}{3}}\sqrt[3]{2}x^3[/tex]

[tex]\hookrightarrow 32\sqrt[3]{2}x^{\frac{7}{3}}-4\cdot \:2^{\frac{2}{3}}\sqrt[3]{2}x^3[/tex]

[tex]\hookrightarrow 32x^2 \sqrt[3]{2x} - 8x^3[/tex]

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