Answer:
Step-by-step explanation:
#1.
2x² + 24x + 10 = 0
2(x² + 12x + 5) = 0
2[ x² + 2(6)x + 6² - 6² + 5 ] = 0
2[(x + 6)² - 31] = 0
2( x + 6 - √31 )( x + 6 + √31 ) = 0
[tex]x_{1}[/tex] = - 6 + √31
[tex]x_{2}[/tex] = - 6 - √31
#2.
f(x) = 3x² - 36x - 12
f(x) = 3( x² - 12x - 4 )
f(x) = 3 [ x² - 2(6)x + 6² - 6² - 4 ]
f(x) = 3 [( x - 6 )² - 40 ]
f(x) = 3( x - 6 )² - 120
