In ∆RAM and ∆REP
Let's check ratio
[tex]\\ \sf{:}\longrightarrow \dfrac{AR}{RE}=\dfrac{4}{12}=\dfrac{1}{3}[/tex]
[tex]\\ \sf{:}\longrightarrow \dfrac{RM}{RP}=\dfrac{2}{6}=\dfrac{1}{3}[/tex]
Hence
option B is correct
Answer:
[tex]second \: one \: is \: correct[/tex]
