tolsonem6
tolsonem6 tolsonem6
  • 16-10-2021
  • Mathematics
contestada

PLEASE ANSWER FAST!
Find BDC.
BDC=​

PLEASE ANSWER FASTFind BDC BDC class=

Respuesta :

prasamsharayamajhi
prasamsharayamajhi prasamsharayamajhi
  • 16-10-2021

Answer:

angle BDC= 95°............

Answer Link
priyodiptobasak
priyodiptobasak priyodiptobasak
  • 16-10-2021

Step-by-step explanation:

<NDC=<NCD (Given)

<NCD=35°.

<CAN=<DBN (Given)

<DBN=50°.

therefore, <CND = 180-35-35=110.

and <CND and <DNB are linear pair.

<CND+<DNB=180°

<DNB=180-110

<DNB=70.

therefore, <BDN = 180-50-70 = 60.

therefore, <BDC= 35°+60°=95°.

hope this helps you.

Answer Link

Otras preguntas

Simplify: 1/3(-9/10)(-x)(-x)
Read the paragraph Elianna did not let this or any other disappointment discourage her, and, as graduation approached, she upped her game with her parents. What
what’s the vocabulary term for y - y1 = m(x - x1) is in ___ form.
Why the derivative of (x^2/a^2) = (2x/a^2)? ​
which is terminating or non terminating..........125/441​
Which atom's valence electrons experience the greatest effective nuclear charge? 1)the valence electrons in In 2)the valence electrons in Sr 3)the valence elect
I need help with my Math please!!
happy day of love and friendship to allI wish you a happy day and enjoy those loves that are true, because of those there are very few ​
1 Complete with the correct form of nuestro. 1. _ escuela está en la calle Potosí. 2. En general, profesores son simpáticos. 3. clases no son difíciles. 4. curs
easy to sing along (singable)​