Answer:
[tex] \blue{A = 24~ft^2} [/tex]
Step-by-step explanation:
This figure is a trapezoid with bases of 10 ft and 6 ft and height of 3 ft.
[tex] A = \dfrac{b_1 + b_2}{2}h [/tex]
[tex] A = \dfrac{10~ft + 6~ft}{2} \times 3~ft [/tex]
[tex] \blue{A = 24~ft^2} [/tex]
