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2.24g of iron combine with 0.96g of oxygen to form an oxide of iron. Determine the formula of this oxide of iron and use it to complete the balanced equation

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Answer:

See Explanation

Explanation:

Let us find the number of moles of each element

For iron = 2.24g/56 = 0.04 moles

For oxygen = 0.96 g/16 = 0.06 moles

Then we divide by the lowest ratio;

0.04/0.04      and     0.06/0.04

1                      and     2

We Thus obtain 1 : 1.5

Multiplying through by 2 we have; 2 : 3

The formula of the oxide formed is Fe2O3

The balanced equation is;

4Fe + 3O2 ------> 2Fe2O3

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