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On the midnight shift, the number of patients with head trauma in an emergency room has the probability distribution shown below. x 0 1 2 3 4 5 Total P(x) .02 .31 .25 .19 .13 .10 1.00 (a) Calculate the mean and standard deviation. (Round your mean value to 2 decimal places and standard deviation to 3 decimal places.) Mean Standard deviation (b) Describe the shape of this distribution. multiple choice Skewed to the right Skewed to the left Symmetric

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Answer:

Mean = 2.40

Standard deviation = 1.356

Step-by-step explanation:

Given the data:

X :___ 0 __1 ___ 2 ___ 3 __ 4 __ 5 __Total

P(x)_0.02_0.31_0.25_0.19_0.13 _0.10_ 1.00

The mean [E(X)]

Σx*p(x)

(0*0.02)+(1*0.31)+(2*0.25)+(3*0.19)+(4*0.13)+(5*0.10) = 2.4

The standard deviation :

Std(x) = sqrt[VAR(x)]

Var(x) = ((0^2 * 0.02)+(1^2 * 0.31)+(2^2 * 0.25)+(3^2 * 0.19)+(4^2 * 0.13)+(5^2 * 0.10)) - 2.4^2

Var(X) = 7.6 - 5.76 = 1.84

Std(X) = sqrt(1.84) = 1.356 (3 decimal places)

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