Answer:
[tex]34[/tex]
Step-by-step explanation:
Let the first number be [tex]x[/tex]
The next number be [tex]2[/tex] more than the previous as it is an even number
The second number is [tex]x+2[/tex]
and the last number is [tex]x+4[/tex]
The sum of the numbers is [tex]108[/tex], so the expression will be
[tex]x+(x+2)+(x+4)=108[/tex]
[tex]\Rightarrow 3x+6=108[/tex]
[tex]\Rightarrow x=\dfrac{108-6}{3}[/tex]
[tex]\Rightarrow x=34[/tex]
The smallest of the three numbers is [tex]34[/tex].
