Answer:
The electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.
Explanation:
Given;
thickness of the membrane wall, d = 14 nm = 14 x 10⁻⁹ m
potential of the membrane wall, V = 0.11 V
The electric field in the membrane wall of a living cell is calculated as;
[tex]E = \frac{V}{d} \\\\E = \frac{0.11}{14 \times 10^{-9}} \\\\E = 7.857 \times 10^6 \ V/m[/tex]
Therefore, the electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.
