A 40.0 gram sample of water releases 503 Joules of energy when cooled from 25.0˚C to 22.0˚C. What is the value of the specific heat of water? Round to the nearest hundredth.

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Answer:

Explanation:

i dont know either but im working on it now, i think that you are supposed to use this equation Q = m * ΔT * Cp once i get the answer ill tell you