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Printed circuit cards are placed in a functional test after being populated with semiconductor chips. A lot contains 140 cards, and 20 are selected without replacement for functional testing. a. If 20 cards are defective, what is the probability that at least 1 defective card is in the sample

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Answer:

The probability that at least 1 defective card is in the sample is [tex]0.9644[/tex]

Step-by-step explanation:

Here

N = 140

and n = 20

We will use the below given formula

P(at least 1 defective) = 1 - P( 0 defectives)

P( 0 defectives) =

[tex]= \frac{^{20}C_0 * ^{120}C_{20}}{ ^{140}C_{20}}\\= 0.0356 1-0.0356 \\= 0.9644[/tex]

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