Suppose a lion running at a velocity of 10 m/s east slows
down. After 30 seconds, the lion has stopped. What is the
lion's acceleration?

Respuesta :

Answer:

[tex]a=0.34\ m/s^2[/tex]

Explanation:

Given that,

Initial velocity, u = 10 m/s

Final velocity, v = 0 (stops)

Time, t = 30 s

We need to find the acceleration of the lion.

We know that,

Acceleration = rate of change of velocity

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{10-0}{30}\\\\a=0.34\ m/s^2[/tex]

So, the acceleration of the lion is [tex]0.34\ m/s^2[/tex].