allisonhogan78 allisonhogan78

17-01-2021
Chemistry

contestada

What is the mass of 1.45 moles of silver sulfate?

Respuesta :

cuviulvliy cuviulvliy

17-01-2021

Answer:

449.5 g

Explanation:

Silver sulfate- Ag2SO4

M(Ag)=107 g/mol => M(Ag2)=214 g/mol

M(S)=32 g/mol

M(O)=16 g/mol => M(O4)=64 g/mol

M(Ag2SO4)=310 g/mol

n=1.45 mol

m(Ag2SO4)=M(Ag2SO4)*n=310 g/mol *1.45 mol= 449.5 g

Answer Link

Raniyahh Raniyahh

17-01-2021

The answer is 449.5g

Answer Link

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