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Note: Your answer choices are not clear, thus I have solved the complete question which anyways should be able to clear your concept.

Answer:

The equation of a line that has a slope of -5 and passes through the point (-3,-1) will be:

  • y = -5x - 16

Step-by-step explanation:

Given

  • slope = m = -5
  • point = (-3, -1)

We know that the slope-intercept form of the line equation is

[tex]y=mx+b[/tex]

Here:

  • m is the slope
  • b is the y-intercept

Now, substituting m = -5 and (-3, -1) in the slope-intercept form of the line equation  to determine the y-intercept 'b'

[tex]y=mx+b[/tex]

-1 = -5(-3) + b

switch sides

-5(-3) + b = -1

15 + b = -1

b = -1 - 15

b = -16

Now, substituting m = -5 and b = -16 in the slope-intercept form of the line equation  to determine the equation of a line

[tex]y=mx+b[/tex]

y = -5x + (-16)

y = -5x - 16

Therefore, the equation of a line that has a slope of -5 and passes through the point (-3,-1) will be:

  • y = -5x - 16

Note: Your answer choices are not clear, thus I have solved the complete question which anyways should be able to clear your concept.

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