JuJacuzzi2331 JuJacuzzi2331

17-12-2020
Chemistry

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Calculate the mass of 12.3 moles of MgSO4.

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pzpeter75 pzpeter75

17-12-2020

Answer:

614 034 kg

Explanation:

n = m/Mm

m = n * Mm

Mm(MgSO4) = 1 * 24.3 * 1 * 32.1 * 4 * 16 = 49921.92

m = 12.3 * 49921.92

m = 614 034 kg

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Аноним Аноним

17-12-2020

614 034 kg hope it help out

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