Answer:
1.269 s
Explanation:
The period of oscillation of a simple pendulum is given or expressed with the following relationship
T = 2π√(L/g), where
T is the period of the said pendulum, ?
L is the length of string of the pendulum, 0.4 m
g is the acceleration due to gravity, 9.81 m/s²
On applying the values into the formula, we have
T = 2 * 3.142 * √(0.4/9.81)
T = 6.284 * √0.04077
T = 6.284 * 0.202
T = 1.269 s
Therefore, the period of the pendulum is 1.269 s
