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a 3.00 kg object undergoes an acceleration given by a = (2.00 i + 5.00 j) m/s^2 find the resultant force acting on the object and the magnitude of the resultant force

Respuesta :

SJ2006

F = m.a

F = 3(2 I + 5 j)

F = 6i + 15j is resultant force

Magnitude force = √6+15 = √21

Answer:

(6 i + 15 j) N ,  16.16 N

Explanation:

m = 3 kg, a = ( 2 i + 5 j) m/s^2

Force = mass x acceleration

F = 3 x ( 2i + 5j) = 6 i + 15 j

The resultant force, F = (6 i + 15 j) N

Magnitude of net force is given by

[tex]F = \sqrt{6^{2}+15^{2}}[/tex]

F = 16.16 N