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A child attempts to move a 90.01 kilogram refrigerator in order to retrieve a rubber
ball from behind it. If she is able to slide the refrigerator across the floor with 55
Newtons of force (ignoring friction), what would be its acceleration?

Respuesta :

Answer:

[tex]a=0.611\ m/s^2[/tex]

Explanation:

Given that,

Mass of a refrigerator, m = 90.01 kg

She is able to slide the refrigerator across the floor with 55  N of force.

We need to find the acceleration of the refrigerator.

Let it is a. Using second law of motion:

F = ma

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{55\ N}{90.01\ kg}\\\\a=0.611\ m/s^2[/tex]

So, its acceleration is [tex]0.611\ m/s^2[/tex].

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