Assume that the inspired air is dry air. The vapor pressure of 47 mmHg at 37°C corresponds to a volume and mass of liquid water. If the tidal volume is 500 mL and respiration rate is 12 min−1, how much water is lost from the body per day? Would you expect this to increase or decrease with activity?

Respuesta :

Answer:

Water lost per day will be "378 g".

Explanation:

The volume of air expired per a day will be:

= [tex]12\times 500[/tex]

= [tex]8640 \ L[/tex]

As we know,

The ideal gad law equation will be:

⇒ [tex]PV = nRT[/tex]

⇒ [tex](\frac{47}{760} )\times 8640= n\times 0.082\times 310[/tex]

⇒ [tex]n=21\times 18[/tex]

⇒ [tex]n=378 \ g[/tex]