kevin34007 kevin34007

16-09-2016
Mathematics

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What is the value of ƒ(– 6) when ƒ(x) = x2 + 8x + 10?

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darth666 darth666

16-09-2016

[tex]f(x)= x^{2} +8x+10[/tex]
[tex] f(-6) = (-6)^2+8(-6)+10[/tex]
[tex]f(-6)=36-48+10 = -2[/tex]
[tex]f(-6)=-2[/tex]

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