Answer:
[tex]=\frac{1}{9^5}[/tex]
Step-by-step explanation:
[tex]\frac{9^2}{9^7} \\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\frac{9^2}{9^7}=9^{2-7}\\\\=9^{-5}\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\=\frac{1}{9^5}[/tex]
