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13) Fred is travelling 3.4 m/s and decelerates at a rate of 0.83 m/s until he comes to a stop
How long does this take? How far does he travel during this time?​

Respuesta :

samuelonum1

Answer:

Tt will take 4.04 seconds

Explanation:

In this problem/exercise, we are going to apply the newtons first equation of motion to solve for the time taken

Given that

final velocity= 3.4m/s

initia velocity u= 0m/s

deceleration= 0.84 m/s^2

time t= ?

applying

v=u+at

Substituting our given data into the expression above we have

3.4=0+0.84t

3.4=0.84t

divide both sides by 0.84 we have

3.4/0.84= t

t= 4.04 seconds

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