Respuesta :
Answer:
Magnification, m = 3
Explanation:
It is given that,
Focal length of the lens, f = 15 cm
Object distance, u = -10 cm
Lens formula :
[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}[/tex]
v is image distance
[tex]\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-10)}\\\\v=-30\ cm[/tex]
Magnification,
[tex]m=\dfrac{v}{u}\\\\m=\dfrac{-30}{10}\\\\m=3[/tex]
So, the magnification of the lens is 3.
Answer:
3.00 - Magnification.
Now this is REALLY helpful ( I hope)
Image distance :
