Answer:
The answer is option B
Step-by-step explanation:
secB = 1/cosB
cotB = cosB / sinB
secBcotB is
[tex] \frac{1}{ \cos(B) } \times \frac{ \cos(B) }{ \sin(B) } \\ \\ = \frac{1}{ \sin(B) } \\ \\ But \: \frac{1}{ \sin(B) } = \csc(B) \\ \\ \\ = \csc(B) [/tex]
Hence the identity
Hope this helps you
