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16-06-2020
Mathematics

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Write the equation for the perpendicular bisector of the given line segment.
y = -3x + 5/3
B)y = 3x-2/3
C)y =1/3x-2/3
D)y =1/3x+5/3

Write the equation for the perpendicular bisector of the given line segment y 3x 53 By 3x23 Cy 13x23 Dy 13x53 class=

Respuesta :

16-06-2020

Answer:

C

Step-by-step explanation:

find the equation of the segment two point (-5,5) and (-2,-4)

m=y2-y1/x2-x1 =5-(-4)/-5-(-2) =9/-3 = -3

find b : y= -3x+b

5 =-3(-5) +b

b=-10

the equation is : y=-3x-10

the perpendicular line is y=1/3 x -2/3

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