andrew7832 andrew7832
  • 17-04-2020
  • Mathematics
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Solve 2x^2-3x-5 using the quadratic formula

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Hi1315
Hi1315 Hi1315
  • 17-04-2020

Answer:

[tex]2 {x}^{2} - 3x - 5 \\ 2 {x}^{2} - 5x + 2x - 5 \\ 2 {x}^{2} + 2x - 5x - 5 \\ 2x(x + 1) - 5(x + 1) \\ = (2x - 5)(x + 1)[/tex]

[tex]2x - 5 = 0 \\ 2x = 0 + 5 \\ \frac{2x}{2} = \frac{5}{2} \\ x = \frac{5}{2} [/tex]

[tex]x + 1 = 0 \\ x = - 1[/tex]

hope this helps you.....!

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