littlegenesis2 littlegenesis2

19-07-2016
Mathematics

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A geometric sequence is defined by the explicit formula an=5(-4)^n-1 what is the recursive formula for the nth term of this sequence?

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19-07-2016

Hello,

[tex] a_{n}=5*(-4)^{n-1}\\ a_{n-1}=5*(-4)^{n-2}\\\\ \dfrac{a_{n}}{a_{n-1}}=(-4)^{n-1-(n-2)}=-4\\\\ Formula\ is\ :\\ a_{n}=-4*a_{n-1}\\ a_{1}=5\\ [/tex]

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