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Question 1 (3 points)
A sample of xenon gas has a volume of 6.33 L at a temperature of 35.0 degrees Celsius and a pressure of 342 mmHg. What would the volume
be if the temperature rose to 57.9 degrees celsius and the pressure Increased to 821 mmHg?
Volume =
Liters
Blank 1:

Respuesta :

Answer: V= 2.83 L

Explanation: To find the new volume for Xenon gas we will use Combined Gas Law formula which is P1V1 /T1 = P2V2/T2. For the temperatures given in °C, it must be converted first in Kelvin.

T1 = 35.0 °C + 273 = 308 K

T2 = 57.9 °C +273 = 330.9 K

Derive for V2.

V2 = P1 V1 T2 / T1 P2

=342 mmHg ( 6.33 L) ( 330.9 K) /

308 K ( 821 mmHg )

= 2.83 L

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