Answer:
[TeX](\frac{\pi}{4}, \frac{5\pi}{4})[/TeX]
Step-by-step explanation:
tan(θ)=1 for 0 ≤ θ < 2π
θ= [TeX] Tan^{-1} 1 [/TeX]
θ = [TeX]\frac{\pi}{4}[/TeX]
Tan θ is also positive in the 3rdvq Quadrant,
The Value of θ in the 3rd Quadrant
= [TeX]\frac{\pi}{4}+\pi[/TeX]
=[TeX]\frac{5\pi}{4}[/TeX]
Therefore that values of θ in the interval 0 ≤ θ < 2π that satisfies tan(θ)=1 are:
[TeX](\frac{\pi}{4}, \frac{5\pi}{4})[/TeX]
