Answer:
[tex]P=18.28\ lb/ft^2[/tex]
Explanation:
Given that
d₁ = 4 in
d₂ = 3 in
v₂ = 150 ft/s
We know that ,from continuity equation
A₁v₁= A₂v₂
d₁²v₁ = d₂²v₂
[tex]v_1=\dfrac{3^2}{4^2}\times 150\ ft/s[/tex]
[tex]v_1=84.37\ ft/s[/tex]
Now by using energy equation ,The pressure P is given as
[tex]P=\dfrac{1}{2}(v_2^2-v_1^2)\times \rho\ lb/ft^2[/tex]
[tex]P=\dfrac{1}{2}(150^2-84.37^2)\times 0.002377\ lb/ft^2[/tex]
[tex]P=18.28\ lb/ft^2[/tex]
