Zeemarinclovelypow
Zeemarinclovelypow Zeemarinclovelypow
  • 20-06-2016
  • Chemistry
contestada

What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?

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Hagrid
Hagrid Hagrid
  • 24-06-2016
First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation. 

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis: 

[tex]4.60*10^{-3} g CH4 ( \frac{moleCH4}{16 g CH4}) * ( \frac{2mole O2}{mole CH4}) * ( \frac{32 g O2}{mole O2} ) = 0.0184 g O_{2} [/tex]
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