A wrench released from a state of rest at time t = 0 travels a distance s(t) = 4.9t2 m in t seconds. Estimate the instantaneous velocity v at t = 7 seconds.

Respuesta :

Answer:

  68.6 m/s

Step-by-step explanation:

The instantaneous velocity is ...

  s'(t) = 2(4.9)t = 9.8t

Then ...

  s'(7) = 9.8(7) = 68.6 . . . . meters per second