Answer:
[tex]Mg_{(s)}+Cu^{2+}_{(aq)}\rightarrow Mg^{2+}_{(aq)}+Cu_{(s)}[/tex]
Explanation:
The given cell notation is:-
[tex]Mg_{(s)}|Mg^{2+}_{(aq)}||Cu^{2+}_{(aq)}|Cu_{(s)}[/tex]
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
[tex]X\rightarrow X^{n+}+ne^-[/tex]
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
[tex]X^{n+}+ne^-\rightarrow X[/tex]
The half cell reactions for the above cell notation follows:
Oxidation half reaction: [tex]Mg_{(s)}\rightarrow Mg^{2+}_{(aq)}+2e^-[/tex]
Reduction half reaction: [tex]Cu^{2+}_{(aq)}+2e^-\rightarrow Cu_{(s)}[/tex]
The overall redox reaction is:-
[tex]Mg_{(s)}+Cu^{2+}_{(aq)}\rightarrow Mg^{2+}_{(aq)}+Cu_{(s)}[/tex]
The redox reaction shown by the cell notation represents an electrochemical cell in which magnesium is the anode while copper is the cathode.
A redox reaction is a reaction in which oxidation and reduction reactions occur simultaneously and to the same extent.
In the redox reaction represented by the following cell notation,Mg(s) / Mg2+(aq) // Cu2+(aq) / Cu(s);
The redox reaction represents an electrochemical cell in which magnesium is the anode while copper is the cathode.
Learn more about redox reactions at: https://brainly.com/question/1161855
