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Negative three times a number is at least 57.
a.–3n 2 57; {m\n 5-19)
b. –3n 57, 7|12-19
c. –3n 2 57, {m\n 5 19}
d. -32 > 57, (n\n<-19}

Respuesta :

The option formatting isn't very clear, anyway: given a number x, negative 3 times that number is -3x. If this has to be at least 57, it means that -3x must be greater than or equal to 57:

[tex]-3x\geq 57[/tex]

Dividing both sides by -3 solves the equation, but we have to switch the inequality sign because we're dividing by a negative number:

[tex]x\leq \dfrac{57}{3}=19[/tex]

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