Ngcdavra6nac4aith Ngcdavra6nac4aith

18-05-2016
Mathematics

contestada

Solve the following equation for t.

−2t^2+t+28=0

Respuesta :

18-05-2016

Hello,

-2t²+t+28=0
==>2t²-t-28)=0
==>2t²-8t+7t-28=0
==>2t(t-4)+7(t-4)=0
==>(t-4)(2t+7)=0
==>t=4 or t=-7/2

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