At one instant in time, a rock falling off a cliff experiences an upward force from air resistance at a magnitude of 10 N. The rock itself has a mass of 7 kg. What is the magnitude and direction of the acceleration of the rock at this instant? (Take the magnitude of acceleration due to gravity to be 9.8 m/s2 and indicate direction by using a (-) value for downward and a (+) value for upward.)

(Hint: What is the net force acting on the rock?)

Note: Be careful entering your units! Follow the instructions in the guide posted in the homework section!

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nohemiag nohemiag · Answer 1 · 2019-09-17T05:09:09+02:00

Answer:

a=-8.4 m/s^2

Explanation:

We can use (-) value for downward and a (+) value for upward

The weight of the rock is calculated as follows:

W=mass*gravity

W=7kg*(-9.8m/s^2)

W=-68.8N

The air resistance force makes sense opposite to the weight of the rock:

Fr=+10N

The total force on the rock is:

Ft= Fr+W

Ft=10N-68.8N

Ft=-58.8N

We also know that force is the product of mass by acceleration:

Ft= m*a

Thus:

a= Ft/m

a=-58.8N/7kg

a=-8.4 m/s^2 (downward)