Answer:
[tex]u = 0.057 J/m^3[/tex]
Explanation:
Energy density near the surface of the sphere is given by the formula
[tex]u = \frac{1}{2}\epsilon_0 E^2[/tex]
also for sphere surface we know that
[tex]E = \frac{V}{R}[/tex]
R = radius of sphere
V = potential of the surface
now we have
[tex]u = \frac{1}{2}\epsilon_0 (\frac{V^2}{R^2})[/tex]
now from the above formula we have
[tex]u = \frac{1}{2}(8.85 \times 10^{-12})(\frac{8500^2}{0.075^2})[/tex]
[tex]u = 0.057 J/m^3[/tex]
