Answer:
5000 N/m
Explanation:
Hooke's law for the spring is
[tex] F = k \Delta x[/tex]
where here we have
F = 100 N is the force applied to the spring
k is the spring constant
[tex]\Delta x = 22 cm - 20 cm = 2 cm = 0.02 m[/tex] is the stretching of the spring with respect to its equilibrium position
Solving the equation for k, we find the spring constant:
[tex]k=\frac{F}{\Delta x}=\frac{100 N}{0.02 m}=5000 N/m[/tex]
