varojess varojess
  • 17-04-2019
  • Chemistry
contestada

At what pressure would 14.4 grams of oxygen gas occupy 7.5 liters at a temperature of 375 K?

Respuesta :

superman1987
superman1987 superman1987
  • 27-04-2019

Answer:

1.85 atm.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L (V = 7.5 L).

n is the no. of moles of the gas in mol (n = mass/moar mass = 14.4 g/32.0 g/mol = 0.45 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K).

T is the temperature of the gas in K (T = 375 K).

∴ P = nRT/V = (0.45 mol)(0.0821 L.atm/mol.K)(375 K)/(7.5 L) = 1.85 atm.

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